Naval Architecture 1 – Page 3

Chief Mate MMD

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December 26, 2025

Nov 2021 Nav Arc 1

Q.3 ‘M.V.Hindship’ displacement 8473 MT, KG: 8.84m, FSC: 0.146m, is to be Dry-docked. At the critical instant the GM (f) of the vessel is to be not less than 0.20m. Determine the maximum trim by stern with which she will enter Dry-dock if she is to take to the blocks first at the AP. Also state the arrival dry-dock drafts

2021 0 19 sec read

December 26, 2025

June 2022 Nav Arc 1

Q.2 A ship of L = 200 m, W = 50000 T, MCTC = 250 T-m, KM 10 m, KG 5 m, TPC = 50 T, LCF 105 m, draft F 10.0 m, A 11.0 m, grounds lightly on an isolated rock in falling tide. At low water, the drafts are found to be F 9.5 m, A 11.0 m,

2022 0 36 sec read

December 26, 2025

Apr 2024 PM Nav Arc 1

Q.2 A vessel of displacement 29000 t, LBP 185m, KM 11.50, KG 10.95. Draft Fwd 8.00m, Aft 9.38m, LCF 89.5m, MCTC 410 tm, TPC 29.5 t/cm. The depth of water in the dock is initially 10m. Find the effective GM and drafts Fwd and Aft after the water level has fallen by 1.35m. Answer: Q.3 M.V. Hindship, displacement 9348 T,

2024 0 31 sec read

December 25, 2025

Apr 2025 AM Nav Arc 1

Q.3. M.V. Hindship displacement 12927 T, KG 7.850 m, FSM 1290 TM, is trimmed 0.70 m by the stern. She has to be dry-docked. Calculate:i) Virtual GM of the vessel when her keel takes the blocks all along the length of the vessel.ii) Drafts F and A when she sits overall on the blocks. Answer:

2025 0 16 sec read

December 25, 2025

July 2024 PM Nav Arc 1

Q.1 M. V. Hindship displacing 9500 t and trimmed 0.80 m by stern is to be dry-docked for bottom inspection. KG = 7.92 m, FSM= 1600 tm. Calculate:a) The GM (F) of the vessel before entering the dry-dock.b) The virtual GM of the vessel when her heel taken blocks all along the length of the vessel. Answer:

2024 0 16 sec read