July 2025 AM Nav Arc 1

Q.1 M. V. Hindship sailed from port from drafts F 8.800 m and A 9.200 m resp. with KG 7.850 m and FSM 1950 TM. On her voyage she grounded on an isolated rock, without damage to her hull. The drafts then were observed to be F 8.300 m and A 9.300 m. Determinei) The position w.r.t. AP where the

Jan 2025 PM Nav Arc 1

Q.2 A vessel of L 148 m, LCF 70 m, draft forward 8.00 m, draft aft 9.80 m, TPC 32, MCTC 264 lightly grounds on gently sloping seabed. Soundings taken in that instant showed forward depth as 8.00 m and aft depth as 10.9 m. Find the draft after tide falls by (a) 30 cm (b) 2.00 m Answer:

Oct 2025 PM Nav Arc 1

Q.2 A ship of L = 140m, W = 16000t, LCF=72m, MCTC=190tm, FSM=137tm, KM = 8.2m, KG = 7.2m TPC=24t, draft Fwd = 6.70m. Aft = 8.85m grounds lightly on an isolated rock. The drafts now are found to be fwd 5.90m and aft 9.30m. Calculate the virtual GM and the rise of tide required to refloat the vessel. Answer:

Jan 2025 AM Nav Arc 1

Q.1 A vessel of displacement 29,000 t, length 200m, Fwd draft 7m and Aft Draft 8.5m runs aground without any damage to her hull. Her MCTC 250 tm/cm and TPC 20 t/cm, LCF 105m, FSM 1000 tm, KM 8.5m, KG 7.8m. Tide then falls by 50 cm. The drafts then observed were to be Fwd 7.8m and Aft 7.5m. Calculate

Apr 2025 PM Nav Arc 1

Q.2 A vessel of displacement 24000, LBP = 180, LCF = 94, TPC = 20, MCTC = 200 arrives in D.D. with drafts f =8.20m, A = 9.00m. Determine the residual GM when water level falls by 40 cms after the stern touches the blocks. KG = 7.90m, KM = 8.30m, FSM initial = 2000 Tm. Answer:

Apr 2025 AM Nav Arc 1

Q.3. M.V. Hindship displacement 12927 T, KG 7.850 m, FSM 1290 TM, is trimmed 0.70 m by the stern. She has to be dry-docked. Calculate:i) Virtual GM of the vessel when her keel takes the blocks all along the length of the vessel.ii) Drafts F and A when she sits overall on the blocks. Answer:

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